Symphony.

Hello,

How do I show the current date and time using the Format Date/Time utility?

I’ve tried the exslt:node-set function to pass a node as paramater, but didn’t work.

@rainerborene - Did you see Rowan’s utility which uses EXSLT?

@rainerborene - you should be able to get the current date and time from your symphony parameters ?debug=params.

Or if you want to pull the current date and time via exslt, then first you’ll want declare the exslt namespace in your xsl:stylesheet element like so…

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:date="http://exslt.org/dates-and-times" exclude-results-prefixes="date">

Here’s what you use to get the current date and time, <xsl:value-of select="date:date-time()"/>

Here’s what you use to get just the current date, <xsl:value-of select="date:date()"/>

Because the utility expects a time attribute on the date node it will fail. I get around this by first calling the format-date template with something like:

<xsl:with-param name="date" select="$today"/>
<xsl:with-param name="format" select="'Y M D'"/>

Then the format-time template, splitting the $current-time parameter up.

Alternatively could you try:

<xsl:with-param name="date">
    <date time="{$current-time}"><xsl:value-of select="$today"/></date>
</xsl:with-param>

@bzerangue Thanks, I’ll try that solution.

@nickdunn The format-date template also needs a weekday attribute.

@rainerborene - I made a couple of edits, see bolded items above.

@nickdunn The format-date template also needs a weekday attribute.

Only if you use the W character in the format. If you don’t need day of the week, it doesn’t need the attribute.